Class 11 NEET Chemistry Equilibrium Questions Part 1

2SO2(g)+O2(g)⇌2SO3(g).....(i)
K = 278
By revrsing the equation (i),we get
2SO3(g)⇌2SO2(g)+O2(g)....(ii)
Equilibrium constant for this reaction is
K′=

1

K

=

1

278

By dividing the equation (ii) by 2, we get desired equation
SO3(g)⇌SO2(g)+

1

2

O2(g).....(iii)
Equilibrium constant for this reaction
K′′=√K′=√

1

K

=√

1

278

=0.0599≈0.06 or 6×10−2