Class 12 NEET Chemistry Electrochemistry Questions

Current (I)=5 ampere and time (t)=40 minutes =2400 seconds.
Amount of electricity passed (Q)=I×t=5×2400 =12000C
Now , Zn2++2e−→Zn (1‌mole=65.39)
since, two charges (i.e., 2×96500 C) deposits 65.39‌gm of zinc,
therefore 12000 C will deposit =

65.39×12000

2×96500

=4.065g of zinc