Class 12 NEET Chemistry Electrochemistry Questions

Question : 48 of 74

Marks: +1, -0

Consider the following relations for emf of an electrochemical cell
(i) EMF of cell = (Oxidation potential of anode) - (Reduction potential of cathode)
(ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode)
(iii) EMF of cell = (Reductional potential of anode) + (Reduction potential of cathode)
(iv) EMF of cell = (Oxidation potential of anode) - (Oxidation potential of cathode)
Which of the above relations are correct?

(2010 Mains)

(iii) and (i)
(i) and (ii)
(iii) and (iv)
(ii) and (iv)

Validate

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