Limiting molar conductivity of NH_4OH [i,.e. \Lambda^\circ_{m[NH_4OH]}] is equla to (2012)

Correct Answer is : Λ°m(NH4Cl)+Λ°m(NaOH)−Λ°m(NaCl)

\Lambda^\circ_{m(NH_4Cl)}+\Lambda^\circ_{m(NaCl)}-\Lambda^\circ_{m(NaOH)}

\Lambda^\circ_{m(NaOH)}+\Lambda^\circ_{m(NaCl)}-\Lambda^\circ_{m(NH_4Cl)}

\Lambda^\circ_{m(NH_4OH)}+\Lambda^\circ_{m(NH_4Cl)}-\Lambda^\circ_{m(HCl)}

\Lambda^\circ_{m(NH_4Cl)}+\Lambda^\circ_{m(NaOH)}-\Lambda^\circ_{m(NaCl)}

Class 12 NEET Chemistry Electrochemistry Questions

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Limiting molar conductivity of NH4OH [i,.e. Λ°m[NH4OH]] is equla to

(2012)

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