Find the emf of the cell in which the following reaction takes place at 298 {K} {Ni}( {s})+2 {Ag}^{+}(0.001 {M}) \to {Ni}^{2+}(0.001 {M})+2 {Ag}( {s}) ( Given that {E}_{\text{cell }}^{\circ}=10.5 {V}, {2.303 {RT}}/{ {F}}=0.059 at 298 {K}) [NEET-2022]

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Class 12 NEET Chemistry Electrochemistry Questions

Question : 11 of 74

Marks: +1, -0

Find the emf of the cell in which the following reaction takes place at 298K
Ni(s)+2Ag+(0.001M)→Ni2+(0.001M)+2Ag(s)
( Given that E‌cell ‌∘=10.5V,‌

2.303RT

=0.059 at 298K)

[NEET-2022]

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