Three thermochemical equations are given below (i) {C}_{\text{(graphite) }}+ {O}_{2(g)} \to {CO}_{2(g)} ; ∆_r H^{\circ}=x {kJ} {mol}^{-1} (ii) {C}_{\text{(graphite) }}+\frac{1}{2} {O}_{2(g)} \to {CO}_{(g)} ; ∆_r H^{\circ}=y {kJ} {mol}^{-1} (iii) {CO}_{(g)}+\frac{1}{2} {O}_{2(g)} \to {CO}_{2(g)} ; ∆_{r} H^{\circ}=z {k} {J} {mol}^{-1} Based on the above equations, find out which of the relationship given below is correct. (Karnataka NEET 2013)

Class 11 NEET Chemistry Chemical Thermodynamics

Question : 33 of 96

Marks: +1, -0

Three thermochemical equations are given below

(i) C‌(graphite) ‌+O2(g)→CO2(g);∆rH∘=xkJmol−1
(ii) C‌(graphite) ‌+‌

O2(g)→CO(g);∆rH∘=ykJmol−1
(iii) CO(g)+‌

O2(g)→CO2(g);∆rH∘=zkJmol−1

Based on the above equations, find out which of the relationship given below is correct.

(Karnataka NEET 2013)

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