Class 12 NEET Chemistry Chemical Kinetics Questions

A+B→C
Let rate =k[A]x[B]y
where order of reaction is (x+y) .
Putting the values of exp. 1,2, and 3, we get following equations.
0.10=k[0.012]x[0.035]y...(i)
0.80=k[0.024]x[0.070]y ...(ii)
0.10=k[0.024]x[0.035]y ...(iii)
Dividing (ii) by (iii), we get

0.80

0.10

=(

0.070

0.035

)y
⇒2y=8⇒y=3
Keeping [A] constant, [B] is doubled, rate becomes 8 times.
Dividing eq. (iii) by eq. (i), we get

0.10

0.10

=(

0.024

0.012

)x
⇒2x=1⇒x=0
Keeping [B] constant, [A] is doubled, rate remains unaffected.
Hence, rate is independent of [A]
rate ∝[B]3.