Class 12 NEET Chemistry Chemical Kinetics Questions

Let the rate equation is
‌ Rate ‌=k[A]]x[B]y
Therefore, we can write
‌2×10−3=k[0.1]x[0.1]y ...........(i)
‌4×10−3=k[0.2]x[0.1]y ...........(ii)
‌1.6×10−2=k[0.2]x[0.2]y ...........(iii)
‌‌ (ii) ‌÷‌ (i); ‌
‌‌

4×10−3

2×10−3

=‌

k[0.2]x[0.1]y

k[0.1]x[0.1]y

‌⇒‌‌‌

2

1

=‌

(0.2)x

(0.1)x

=(‌

2

1

)x
‌∴‌‌x=1
‌‌ (ii) ‌÷‌ (iii); ‌
‌‌

4×10−3

1.6×10−2

=‌

k[0.2]x[0.1]y

k[0.2]x[0.2]y

‌⇒‌‌‌

1

4

=‌

(0.1)y

(0.2)y

=(‌

1

2

)y
‌∴‌‌y=2
‌∴‌‌‌ Rate ‌=k[A]1[B]2
First order with respect to A while second order with respect to B.