For a chemical reaction 4 {\A}+3 {\B} \to 6 {\C}+9 {\D} rate of formation of {\C} is 6 \times 10^{-2} {\mol} {\L}^{-1} {\s}^{-1} and rate of disappearance of A is 4 \times 10^{-2} {\mol} {\L}^{-1} s^{-1}. The rate of reaction and amount of B consumed in interval of 10 seconds, respectively will be : [NEET Re-2022]

Correct Answer is : 1×10−2molL−1s−1 and 30×10−2molL−1

10 \times 10^{-2} {\mol} {\L}^{-1} {\s}^{-1} and 30 \times 10^{-2} {\mol} {\L}^{-1}

1 \times 10^{-2} {\mol} {\L}^{-1} {\s}^{-1} and 30 \times 10^{-2} {\mol} {\L}^{-1}

10 \times 10^{-2} {\mol} {\L}^{-1} {\s}^{-1} and 10 \times 10^{-2} {\mol} {\L}^{-1}

1 \times 10^{-2} {\mol} {\L}^{-1} {\s}^{-1} and 10 \times 10^{-2} {\mol} {\L}^{-1}

Class 12 NEET Chemistry Chemical Kinetics Questions

Question : 16 of 75

Marks: +1, -0

For a chemical reaction
4A+3B→6C+9D
rate of formation of C is 6×10−2‌mol‌L−1‌s−1 and rate of disappearance of A is 4×10−2‌mol‌L−1 s−1. The rate of reaction and amount of B consumed in interval of 10 seconds, respectively will be :

[NEET Re-2022]

10×10−2‌mol‌L−1‌s−1 and 30×10−2‌mol‌L−1
1×10−2‌mol‌L−1‌s−1 and 30×10−2‌mol‌L−1
10×10−2‌mol‌L−1‌s−1 and 10×10−2‌mol‌L−1
1×10−2‌mol‌L−1‌s−1 and 10×10−2‌mol‌L−1

Validate

Go to Question:

Prev Question

Next Question