Class 11 NEET Chemistry Chemical Bonding And Molecular Structure Part 1

Hybridisation of Br in BrO3−:
H=

1

2

(7+0−0+1)=4i.e, sp3 hybridisation
Hybridisation of Xe in XO−3:
H=

1

2

(8+0−0+0)=4 i.e sp3 hybridisation
In both BrO3− and XeO3.the central is sp3 hybridised and contains one lone pair of electrons, hence in both the cases, the structure is trigonal pyramidal.