NEET 2024 Re Exam Physics and Chemistry Paper

Section: Chemistry

Question : 90 of 100

Marks: +1, -0

The standard cell potential of the following cell Zn‌|Zn2+(aq)|‌Fe‌‌2+(aq)∣Fe is 0.32 V . Calculate the standard Gibbs energy change for the reaction :
Zn( s)+Fe2+(aq)⟶Zn2*(aq)+Fe( s)
(Given : 1F=96487C )

[NEET 2024 Re]

−61.75‌kJ‌mol−1
+5.006‌kJ‌mol−1
−5.006‌kJ‌mol−1
+61.75‌kJ‌mol−1

Validate

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