The standard Gibbs energy change for the given cell reaction will be \text{ (Given: } {\E}_{ {\Al}^{3+} \/ {\Al}}^{\circ}=-1.66 {\V} \text{ and } {\E}_{ {\Cu}^{2+} \/ {\Cu}}^{\circ}=0.34 {\V} \text{ ) } 2 {\Al}( { s})+3 {\Cu}^{2+}( {\aq}) \to 2 {\Al}^{3+}( {\aq})+3 {\Cu}( { s})

Correct Answer is : −1158kJmol−1

NEET 2024 Model Paper

Question : 80 of 200

Marks: +1, -0

The standard Gibbs energy change for the given cell reaction will be
‌ (Given: ‌EAl3+∕Al∘=−1.66V‌ and ‌ECu2+∕Cu∘=0.34V‌ ) ‌
2‌Al( s)+3Cu2+(aq)→2Al3+(aq)+3‌Cu( s)

−579‌kJ‌mol−1
−1158‌kJ‌mol−1
−386‌kJ‌mol−1
−965‌kJ‌mol−1

Validate

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