The position of a particle is given by \overrightarrow{r}(t)=4 t \stackrel{\^}{i}+2 t^2 \stackrel{\^}{j}+5 \stackrel{\^}{k} where t is in seconds and r in metre. Find the magnitude and direction of velocity {\v}( {\t}), at {\t}=1 { s}, with respect to x-axis [NEET 2023 mpr]

Correct Answer is : 4√2ms−1,45∘

4 \sqrt{2} {\ms}^{-1}, 45^{\circ}

4 \sqrt{2} {\ms}^{-1}, 60^{\circ}

3 \sqrt{2} {\ms}^{-1}, 30^{\circ}

3 \sqrt{2} {\ms}^{-1}, 45^{\circ}

NEET 2023 Physics and Chemistry Solved Paper Code C4 (Manipur)

Question : 9 of 100

Marks: +1, -0

The position of a particle is given by

→

(t)=4t

+2t2

where t is in seconds and r in metre. Find the magnitude and direction of velocity v(t), at t=1 s, with respect to x-axis

[NEET 2023 mpr]

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