The vibrations of string of length 60 {\cm} fixed at both ends are represented by the equations y=4 \sin (\pi x \/ 15) \cos (96 \pi t) where {\x} and {\y} are in {\cm} and {\t} in { s}. The maximum displacement at x=5 {\cm} is :-

NEET 2023 Model Paper 2

Question : 49 of 200

Marks: +1, -0

The vibrations of string of length 60‌cm fixed at both ends are represented by the equations
y=4sin‌(πx∕15)‌cos(96πt)
where x and y are in cm and t in s. The maximum displacement at x=5‌cm is :-

2√3‌cm
4‌cm
zero
4√2‌cm

Validate

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