Magnetic field in a plane EM wave is given by B_z=2 \times 10^{-7} \sin (0.5 \times 10^3 {\x}-1.5 \times 10^{11} {\t}) {\T} then electric field is given by :-

Correct Answer is : Ey=60sin(0.5×103x−1.5×1011t)V∕m

E_z=60 \sqrt{2} \sin (0.5 \times 10^3 {\x}-1.5 \times 10^{11} {\t}) {\V} \/ {\m}

E_z=60 \sin (0.5 \times 10^3 {\x}-1.5 \times 10^{11} {\t}) {\V} \/ {\m}

{\E}_{ {\y}}=60 \sqrt{2} \sin (0.5 \times 10^3 {\x}-1.5 \times 10^{11} {\t}) {\V} \/ {\m}

E_y=60 \sin (0.5 \times 10^3 {\x}-1.5 \times 10^{11} {\t}) {\V} \/ {\m}

NEET 2023 Model Paper 2

Question : 4 of 200

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Magnetic field in a plane EM wave is given by Bz=2×10−7sin‌(0.5×103x−1.5×1011t)T then electric field is given by :-

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