An electromagnetic wave propagates in a medium, whose electric field vector is given as \E=200 \sin (18 \\times10^{8} t+8 x) {\V} {\m}^{-1}. Refractive index of medium and amplitude of magnetic field will be

Correct Answer is : µ=43;B0=89×10−6T

\\mu=\frac{3}{2} ; \B_{0}=\frac{2}{3} \\times10^{-6} {\T}

\\mu=\frac{4}{3} ; \B_{0}=\frac{2}{3} \\times10^{-6} {\T}

\\mu=\frac{3}{2} ; \B_{0}=\frac{8}{9} \\times10^{-6} {\T}

\\mu=\frac{4}{3} ; \B_{0}=\frac{8}{9} \\times10^{-6} {\T}

NEET 2022 Model Paper 3

Question : 34 of 200

Marks: +1, -0

An electromagnetic wave propagates in a medium, whose electric field vector is given as E=200‌sin(18×108t+8x)‌V‌m−1. Refractive index of medium and amplitude of magnetic field will be

µ=
3
2
;B0=
2
3
×10−6T
µ=
4
3
;B0=
2
3
×10−6T
µ=
3
2
;B0=
8
9
×10−6T
µ=
4
3
;B0=
8
9
×10−6T

Validate

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