A particle moving in a circle of radius R with a uniform speed takes a time T to complete one revolution. If this particle were projected with the same speed at an angle ' \\theta ' to the horizontal, the maximum height attained by it equals 4 R. The angle of projection, \\theta, is then given by : [NEET 2021]

Correct Answer is : θ=sin−1(2gT2π2R)1∕2

\\theta=\cos ^{-1}({g T^{2}}/{\\pi^{2} R})^{1 \/ 2}

\\theta=\cos ^{-1}({\\pi^{2} R}/{g T^{2}})^{1 \/ 2}

\\theta=\sin ^{-1}({\\pi^{2} R}/{g T^{2}})^{1 \/ 2}

\\theta=\sin^{-1}({2g T^{2}}/{\\pi^{2} R})^{1 \/ 2}

NEET 2021 Physics and Chemistry

Question : 50 of 100

Marks: +1, -0

A particle moving in a circle of radius R with a uniform speed takes a time T to complete one revolution. If this particle were projected with the same speed at an angle ' θ ' to the horizontal, the maximum height attained by it equals 4R. The angle of projection, θ, is then given by :

[NEET 2021]

θ=cos−1(
gT2
π2R
)1∕2
θ=cos−1(
π2R
gT2
)1∕2
θ=sin−1(
π2R
gT2
)1∕2
θ=sin−1(
2gT2
π2R
)1∕2

Validate

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