NEET 2021 Physics and Chemistry

Equation of displacement of particle executing SHM is given by x=A‌sin(ωt+ϕ).......(I)
Potential energy of particle executing SHM is given by
U=

1

2

kx2
=

1

2

kA2sin2(ωt+ϕ) .......(II)
From I and II, it is clear that
Time period of x=A‌sin(ωt+ϕ) is
T1=

2π

ω

⇒ frequency n1=

ω

2π

while time period of x2=A2sin2(ωt+ϕ) is
T2=

π

ω

⇒ frequency n2=

ω

π

Hence n2=2n1