If \overrightarrow{{A}}=2 \stackrel{\^}{{i}}+\sqrt{7} \stackrel{\^}{{j}} and \overrightarrow{{B}}=5 \stackrel{\^}{{i}}+\\sqrt 7{{j}}^{\^} -3\stackrel{\^}{{k}},then the vector whose magnitude is equal to \overrightarrow{{A}} .\overrightarrow{ {B}} and parallel to \overrightarrow{{B}}-\overrightarrow{{A}} is :

Correct Answer is : 17√2(^i−^k)

{17}/{\\sqrt{2}(\stackrel{\^}{{k}}-\stackrel{\^}{{j}})

{17}/{\\sqrt{2}(\stackrel{\^}{{i}}-\stackrel{\^}{{k}} )

3\stackrel{\^}{{i}}-3\stackrel{\^}{{k}}

3\stackrel{\^}{{k}}-3\stackrel{\^}{{i}}

NEET 2021 Model Test Paper 5

Question : 12 of 180

Marks: +1, -0

→

+√7

and

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+√7

−3

,then the vector whose magnitude is equal to

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and parallel to

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−

→

is :

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