If ionisation energy of an element is as follows :{X}\to{X}^{+}+1 {e}^{-} ; 1 {E}_{1} = {\x} {\k} {\J} \/ {\mol} {X}^{+}\to{X}^{2+}+1 {e}^{-} ; 1 {E}_{2} = 1.5{\x} {\k} {\J} \/ {\mol} {X}^{2+}\to{X}^{3+}+1 {e}^{-} ; \I {E}_{3} =15 {\x} {\k} {\J} \/ {\mol} This element may have the electronic configuration :-

NEET 2021 Model Test Paper 1

Question : 55 of 180

Marks: +1, -0

If ionisation energy of an element is as follows :X→X++1e−;1E1 =xkJ∕mol
X+→X2++1e−;1E2 =1.5xkJ∕mol
X2+→X3++1e−;IE3 =15xkJ∕mol
This element may have the electronic configuration :-

ns1
ns2
ns2 np4
ns2 np3

Validate

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