A body of mass 5 kg under the action of constant force F ^{\to}= F_xi^{\^} + F_vj^{\^} has velocity at t = 0s as v^{\to} = (6i ^{\^}- 2 j^{\^}) m/s and at t = 10s as v^{\^} = +6j^{\^} m/s. The force F^{\to}is

Correct Answer is : (−3^i+4^j)N

NEET 2020 Model Question Paper 3

Question : 2 of 180

Marks: +1, -0

A body of mass 5 kg under the action of constant force

→

=Fx

+Fv

has velocity at t = 0s as

→

=(6

−2

) m/s and at t = 10s as

=+6

m/s. The force

→

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