A light whose frequency is equal to 6 \times 10^14 Hz is incident on a metal whose work function is 2 eV. [h = 6.63 \times 10^{–34} Js, 1 eV = 1.6 \times 10^{–19} J). The maximum energy of the electrons emitted will be:

NEET 2020 Model Question Paper 2

Question : 20 of 180

Marks: +1, -0

A light whose frequency is equal to 6×1014 Hz is incident on a metal whose work function is 2 eV. [h = 6.63×10–34 Js, 1eV=1.6×10–19 J). The maximum energy of the electrons emitted will be:

2.49 eV
4.49 eV
0.49 eV
5.49 eV

Validate

Go to Question:

Prev Question

Next Question