The position vector of a particle is {r^{\to}}=(a \cos \\omega t) {i^{\^}}+(a \sin \\omega t) {j^{\^}}. The velocity of the particle is

Correct Answer is : Perpendicular to the position vector

Parallel to the position vector

Perpendicular to the position vector

NEET 2019 Model Question Paper 2

Question : 120 of 174

Marks: +1, -0

The position vector of a particle is

→

=(a‌cos‌ω‌t)

+(a‌sin‌ω‌t)

. The velocity of the particle is

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