Two particles {\A} and {\B}, move with constant velocities \overrightarrow{v_1} and \overrightarrow{v_2}. At the initial moment their position vectors are \overrightarrow{r_1} and \overrightarrow{r_2} respectively. The condition for particles A and B for their collision is [NEET 2015]

Correct Answer is : →r1−→r2|→r1−→r2|=→v2−→v1|→v2−→v1|

\overrightarrow{r_1} \times \overrightarrow{v_1}=\overrightarrow{r_2} \times \overrightarrow{v_2}

\overrightarrow{r_1}-\overrightarrow{r_2}=\overrightarrow{v_1}-\overrightarrow{v_2}

\overrightarrow{{r_1}-\overrightarrow{r_2}}/\overrightarrow{{| {r_1}-\overrightarrow{r_2} |}}= \overrightarrow{{v_2}-\overrightarrow{v_1}}/\overrightarrow{{| {v_2}-\overrightarrow{v_1} |}}

\overrightarrow{r}_1 \cdot \overrightarrow{v_1}=\overrightarrow{r_2} \cdot \overrightarrow{v_2}

NEET 2015 Physics and Chemistry Paper

Question : 6 of 91

Marks: +1, -0

Two particles A and B, move with constant velocities

→

and

→

. At the initial moment their position vectors are

→

and

→

respectively. The condition for particles A and B for their collision is

[NEET 2015]

→
r1
×
→
v1
=
→
r2
×
→
v2
→
r1
−
→
r2
=
→
v1
−
→
v2
‌
→
r1
−
→
r2
|
→
r1
−
→
r2
|
=‌
→
v2
−
→
v1
|
→
v2
−
→
v1
|
→
r
1⋅
→
v1
=
→
r2
⋅
→
v2

Validate

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