A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x)=\betax^{-2n} where β and n are constants and x is the position of the particle. The acceleraion of the particle asa function of x, is given by : [NEET 2015 C]

Correct Answer is : −2nβ2x−4n−1

NEET 2015 Physics and Chemistry Cancelled Paper

Question : 49 of 90

Marks: +1, -0

A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to
v(x)=βx−2n
where β and n are constants and x is the position of the particle. The acceleraion of the particle asa function of x, is given by :

[NEET 2015 C]

−2nβ2x−4n−1
−2nβ2x−2n+1
−2nβ2e−4n+1
−2nβ2x−2n−1

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