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Consider the following for the next two (02) items that follow:Let
, and
be three vectors such that
+++=0 and
||=10,||=6 and
||=14[NDA II 2016]
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Question : 64 of 101
Marks:
+1,
-0
Solution:
Since
++=0⇒+=−⇒|+|=|−|=||⇒|+|2+2(⋅)=||2⇒(10)2+(6)2+2(.)=(14)2⇒2(⋅)=60⇒⋅=30⇒cos‌θ===⇒θ=cos−1()⇒θ=60°
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