NDA Math Three Dimensional Geometry

Equation of line ‌

x−1

2

=‌

y−2

3

=‌

z−3

4

So, Direction ratio of line is 2,3, and 4 and line passing through point (1,2,3)
If lines given by plane then point satisfy the equation of plane.
Option 1: x+y+z=6,x+2y−3y=−4
x+y+z=2×1+3×1+4×1=9≠0
So, option 1 is wrong.
Option 2: x+2y−2z=−1,4x+4y−5z−3=0
x+2y−2z=2+2×3−2×4=2+6−8=0
4x+4y−5z=4×2+4×3−5×4=8+12−20=0
Now
x+2y−2z=1+2×2−2×3=−1
4x+4y−5z−3=4×1+4×2−5×3−3=0
So point (1,2,3) lies on the plane
So, option 2 is correct.