What is the area of the triangle with vertices({x}_{1}, {1}/{{x}_{1}}),({x}_{2}, {1}/{{x}_{2}}),({x}_{3}, {1}/{{x}_{3}}) ? [NDA II 2018]

Correct Answer is : |(x1−x2)(x2−x3)(x3−x1)2x1x2x3|

|(x_{1}-x_{2})(x_{2}-x_{3})(x_{3}-x_{1})|

| {({x}_{1}-{x}_{2})({x}_{2}-{x}_{3})({x}_{3}-{x}_{1})}/{{x}_{1}{x}_{2}{x}_{3}}|

| {({x}_{1}-{x}_{2})({x}_{2}-{x}_{3})({x}_{3}-{x}_{1})}/{2{x}_{1}{x}_{2}{x}_{3}}|

NDA Math Properties of Triangles

Question : 9 of 16

Marks: +1, -0

What is the area of the triangle with vertices(x1,‌‌

),(x2,‌‌

),(x3,‌‌

) ?

[NDA II 2018]

Go to Question:

Prev Question

Next Question