NDA Math Probability Part 2

Statement 1:
If A and B are mutually exclusive events, then P(A∩B)=0.
We know that P(A∪B)=P(A)+P(B)−P(A∩B)=0.6+0.6=1.2>1
This contradicts ∵ probability of any event say A:0≤P(A)≤1.
Hence statement 1 is wrong.
Statement 2:
Given: P(A∣B)=1
As we know, P(A∣B)=‌

P(A∩B)

P(B)

=1
⇒B⊂eqA
⇒P(B∣A)=‌

P(A∩B)

P(A)

=‌

P(A∪B)

P(A)

=‌

P(A)

P(A)

=1
Hence, statement2 is true.