NDA Math Miscellaneous

Consider the following equations,
2p+3q=18
(2p+3q)2=324
4p2+12pq+9q2=324...(1)
4p2+4pq−3q2=36...(2)
Subtracting equation 2 from 1, we get
1 - 2
⇒8pq+12q2=288
⇒4q(2p+3q)=288
⇒4q(18)=288
⇒q=

288

72

By substituting the value of ‘q’ so obtained, we get
2p+3q=18
2p+3(4)=18
2p+12=18
2p=6
p=3
∴p=3,q=4
Hence the required value of the given expression is
2p+q
=2(3)+4
=10