NDA Math Indefinite Integrals

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Question : 24 of 38

Marks: +1, -0

∫(lnx)−1dx−∫(lnx)−2dx is equal to

[NDA II 2017]

x(lnx)−1+c
x(lnx)−2+c
x(lnx)+c
x(lnx)2+c

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