NDA Math Differential Equation

Consider statement 1

dy

dx

=f(x)+x

dy

dx

=y+x

dy

dx

−y=x
IF=e∫−1.dx=e−x
Hence, the solution of the given differential equation is
ye−x=∫xe−xdx+C
ye−x=−xe−x−∫1.−e−xdx+C
ye−x=−xe−x−e−x+C
y=−x−1+Cex
‘y’ is not in g(x)+c form.
Therefore, we can observe that statement 1 is false.
Consider statement 2.
(

dy

dx

)2=y
order = 1,degree = 2
Therefore,statement 2 is correct