What is the solution of the differential equation \ln( \frac{dy}{dx})=ax+by ? [NDA II 2018]

Correct Answer is : 1aeax+1be−by=c

\frac{1}{a}e^{ax}+ \frac{1}{b}e^{by}=c

\frac{1}{{a}}{e}^{{ax}}+ \frac{1}{{b}}{e}^{-{by}}={c}