NDA Math Coordinate System and Straight Line

CALCULATION:
Given: (p,p−3),(q+3,q) and (6,3) are three points in a 2D plane.
Statement 1: The points lie on a straight line.
As we know that, if three points A(x1,y1),B(x2,y2) and C(x3,y3) aresaid to be collinear if the area of ∆ABC is zero i.e |

x1	y1	1
x2	y2	1
∣x3	y3	1

|=0
Let A=(p,p−3),B=(q+3,q) and C=(6,3)
⇒|

p	p−3	1
q+3	q	1
q+3	3	1

| =p(q−3)−(p−3)(q+3−6)+1(3q+9−6q)
⇒|

p	p−3	1
q+3	q	1
q+3	3	1

|=0
So, as we can see that area of triangle ABC=0 for any value of p and q.
Hence, statement 1 is true.
Statement 2:
The points alwayslie in the first quadrant only for any value of p and q.
As we can see that, for any value of p and q it is not necessary that the points lies in the first quadrant only.
Hence, statement 2 is false.
Hence, the correct option is 1.