NDA Math Application of Derivatives

For continuity at x=2.
So, RHL = LHL
⇒f(x) is continuous at x=2.
For differentiability at x=2.
=

lim

h→0

‌‌

37−2−h−35

h

=−1
LHD≠RHD
⇒f(x) is not differentiable at x=2.
To check 2.
For x=2
On putting x=2
f(x)=3(16−‌‌

13

3

)=35
On putting x=1
So f(x) attains greatest value at x=2.