NCHMCT JEE 2020 Question Paper with solutions for online practice

Question : 86 of 200

Marks: +1, -0

Find the least number which when divided separately by

15,20,36

and 48 leaves 3 as remainder in each case.

Solution:

Least number that is divisible by

15,20,36,48

and leaves 3 as remainder

{LCM} \;\; =2 × 2 × 2 × 2 × 3 × 3 × 5

\;\; =144 × 5

\;\; =720

Now, Least Number

=720+3=723

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