NCHMCT JEE 2020 Question Paper with solutions for online practice

Question : 79 of 200

Marks: +1, -0

In an examination, a student had to obtain

33 \%

of the maximum marks to pass. He got 125 marks and failed by 40 marks. The maximum marks were

Solution:

Let the maximum marks be

x

.
Required marks to qualify the exam

⇒ \;\; \;{x × 33}/{100}=125+40

⇒ \;\; \;{33 x}/{100}=165

⇒ \;\; x=\;{165 × 100}/{33}=500

∴ \;\text " Maximum marks "\;=500

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