NCHMCT JEE 2020 Question Paper with solutions for online practice

Question : 72 of 200

Marks: +1, -0

A

and

B

start at the same time with speeds of 40

{km} \/ {h}

and

50 {km} \/ {h}

, respectively. If in covering the journey

A

takes 15 min longer than

B

, the total distance of the journey is

Solution:

Let the distance be

x {km}

.
Time taken by

A=\;{\;\text " Distance "\;}/{\;\text " Speed "\;}

Time taken by

A=\;{x}/{40} {h}

Time taken by

B=\;{x}/{50} {h}

(similarly)
According to the question,

\;{x}/{40}-\;{x}/{50} \;\; =\;{15}/{60}

⇒ \;\; \;{5 x-4 x}/{200} \;\; =\;{15}/{60}

∴ \;\; x \;\; =\;{15}/{60} × 200=50 {km}

Go to Question:

Prev Question

Next Question