NCHMCT JEE 2020 Question Paper with solutions for online practice

Question : 113 of 200

Marks: +1, -0

In an accurate clock, in a period of 2 h

20 {min}

, the minute hand will move over

Solution:

2 h

20 {min}=140 {min}

In every hour the minute hand move over

360^{∘}

.
So, in every minute it moves

=\;{360^{∘}}/{60^{∘}}=6^{∘}

So, in 140 min the minute hand will move over

=6 × 140^{∘}=840^{∘}

Go to Question:

Prev Question

Next Question