NCHMCT JEE 2018 Question Paper with solutions for online practice

Let, 2nd number = x
∴ First number = 2x
$\frac{1}{2}$ of third number $=2\mathit{x}$
∴ Third number = 4x
Sum of three numbers $=56\times 3=168$
$\therefore 2\mathit{x}+\mathit{x}+4\mathit{x}=168$
$\Rightarrow 7\mathit{x}=168$
$\Rightarrow \mathit{x}=\frac{68}{7}=24$
∴ 2nd number $=24$
First number $=24\times 2=48$
Third number$=24\times 4=96$
∴ Numbers are 48, 24, 96.