NCHMCT JEE 2016 Question Paper with solutions for online practice

Question : 41 of 200

Marks: +1, -0

A child is looking for his father. He went 90 metres in the East before turning to his right. He went 20 metres before turning to his right again to look for his father at his uncle’s place 30 metres from this point. His father was not there. From here, he went 100 metres to the North before meeting his father in a street. How far did the son meet his father from the starting point?

80 metres
100 metres
140 metres
260 metres

Validate

Solution:

So, Distance from starting point,
=

√{(100-20)^2+(90-30)^2}

√{(80)^2+(60)^2}

= 100 m

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