NCHMCT JEE 2016 Question Paper with solutions for online practice

Let, C.P. of horse = x
 C.P. of carriage = (3000 – x)
S.P. of horse = x + $\frac{20}{00}$ × x
= $\frac{\mathit{x}+5\mathit{x}}{5}$ = $\frac{6\mathit{x}}{5}$
S.P. of carriage = (3000 - x) - $\frac{10}{100}$ (3000 - x)
= (300 - x) $\frac{99}{10}$
Total C.P. = 3000
Total S.P. = $\frac{6\mathit{x}}{5}$ + (3000 - x) $\frac{9}{10}$
= $\frac{6\mathit{x}}{5}$ + 2700 - $\frac{9\mathit{x}}{10}$ = $\frac{3\mathit{x}}{10}$ + 2700
Profit = $\frac{3\mathit{x}}{10}$ + 2700 - 3000 = $\frac{3\mathit{x}}{10}$ - 300
Profit % = $\frac{\frac{3\mathit{x}}{10}-300}{3000}$ × 100
⇒ 2 = $\left(\frac{3\mathit{x}-3000}{10\times 3000}\right)$ × 100
⇒ 600 = 3x - 3000
⇒ 3x = 3600 ⇒ x = 1200
∴ Cost price of the horse = 1200