NCHMCT JEE 2013 Question Paper with solutions for online practice

Question : 105 of 200

Marks: +1, -0

A cone is 8.4 cm high and the radius of its base is 2.1 cm. It is melted and recast into a sphere. The radius of a sphere is:

Solution:

Let the radius of sphere be r cm
Volume of cone = volume of sphere

1/3

πr^2 h

4/3 πr^3

⇒

1/3

π × 2.1 × 2.1 × 8.4 =

4/3 πr^3

∴

r^3

(2.1)^3

⇒ r = 2.1 cm

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