Given the following 1. class Test { 2. public static void main(String [] args) { 3. printAll(args); 4. } 5. public static void printAll(String[] lines) { 6. for(int i=0;i The static method Thread.currentThread() returns a reference to the currently executingThread object. What is the result of this code?

Correct Answer is : This code will not compile.

Each String in the array lines will print, with exactly a 1-second pause between lines.

Each String in the array lines will print, with no pause in between because this method is not executed in a Thread.

Each String in the array lines will print, and there is no guarantee there will be a pause because currentThread() may not retrieve this thread.

Each String in the lines array will print, with at least a one-second pause between lines.

Multi Threading

Question : 33 of 44

Marks: +1, -0

Given the following

1. class Test {
2.   public static void main(String [] args) {
3.    printAll(args);
4.   }
5.   public static void printAll(String[] lines) {
6.    for(int i=0;i < lines.length; i++){
7.     System.out.println(lines[i]);
8.     Thread.currentThread().sleep(1000);
9.    } 
10.  } 
11. }

The static method Thread.currentThread() returns a reference to the currently executingThread object. What is the result of this code?

Each String in the array lines will print, with exactly a 1-second pause between lines.
Each String in the array lines will print, with no pause in between because this method is not executed in a Thread.
Each String in the array lines will print, and there is no guarantee there will be a pause because currentThread() may not retrieve this thread.
This code will not compile.
Each String in the lines array will print, with at least a one-second pause between lines.

Validate

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