MHTCET 2016 Physics Solved Paper

(a) Force acting on the particle inside magnetic field
FB = qvB sinθ
This force FB provides necessary centripetal force

mv2

r

for circular motion of the charged particle
∴

mv2

r

= qvB sinθ
Now, for particles x and y andfor θ = 90°

mxvx2

rl

=qvxB ....(i)

myvy2

r2

=qvyB ....(ii)
From eqs. (i) and (ii)

mxvx

myvy

=

r1

r2

⇒

mx

my

=

rl

r2

=

r

r2

[∵

vx

vy

=1]