MHTCET 2016 Physics Solved Paper

(d) We know in vertical circle velocity of a particle at lowest point, vl=√5gr
velocity of particle at highest point, vh=√rg
So, KE at highest point of the vertical circle
Kh=

1

2

mrg=

mgr

2

and KE atlowest point of the vertical circle
(Kl)=

1

2

m5gr =

5mgr

2

So, required ratio

Kb

Kl

=

mgr 2

5mgr 2

=

1

5

=0.2