MHTCET 2016 Math Solved Paper

(c) In a trisection of lines in quadrant, angle 90° is divided into three parts and each part contain 30°, as shown in figure
∴ Equation of line OB is
y=tan‌30°‌x ⇒ y=

1

√3

x
x−√3y=0
And equation of line
OC is y=tan‌60°‌x ⇒ y=√3x(√3x−y)=0
∴ Their combined equation is
(x−√3y)(√3x−y)=0
⇒ √3x2−xy - 3xy+√3y2=0
⇒ √3x2−4xy + √3y2=0