MHTCET 14 May 2023 Shift 1 Solved Paper

We know that the density of the element is given by:
ρ=‌

ZM

NAV

Where:
* ρ is the density of the element
* Z is the number of atoms per unit cell (for bcc,z=2 )
* M is the molar mass of the element
* NA is Avogadro's number 6.022×1023mol−1,
*V is the volume of the unit cell
We are given:
‌*ρNA=4.8×1024gcm−3mol−1
‌*M=56gmol−1
Substituting these values into the equation above, we get:
V=‌

ZM

ρNA

=‌

2×56gmol−1

4.8×1024gcm−3mol−1

=2.33×10−23cm3
Therefore, the volume of the unit cell is 2.33×10−23cm3. So the correct answer is Option D.