Find the temperature in degree Celsius if volume and pressure of 2 mole ideal gas is 20dm3 and 4.926 atmospheres respectively. (R=0.0821dm3‌atm‌K−1‌mol−1)
To find the temperature of an ideal gas, we can use the ideal gas equation: PV=nRT where: P is the pressure in atmospheres, V is the volume in liters (dm3), n is the number of moles, R is the gas constant (0.0821dm3‌atm‌K−1‌mol−1), and T is the temperature in Kelvin. Given: We can rearrange the ideal gas equation to solve for T : T=‌
PV
nR
Plugging in the given values: T‌=‌
(4.926‌atm)(20dm3)
(2‌mol)(0.0821dm3‌atm‌K−1‌mol−1)
T‌=‌
98.52‌atm⋅dm3
0.1642dm3‌atm‌mol−1
T‌=600K To convert the temperature from Kelvin to Celsius, use the conversion formula: ‌ Celsius ‌=‌ Kelvin ‌−273.15 For our calculation: ‌‌ Celsius ‌=600K−273.15 ‌‌ Celsius ‌=326.85≈327∘C Therefore, the temperature of the gas in degree Celsius is closest to Option B: 327 .