MHTCET 13 May 2023 Shift 2 Solved Paper

Section: Mathematics

Question : 83 of 150

Marks: +1, -0

The abscissae of two points A and B are the roots of the equation x2+2ax−b2=0 and their ordinates are roots of the equation y2+2py−q2=0. Then, the equation of the circle with AB as diameter is given by

x2+y2−2ax−2py+(b2+q2)=0
x2+y2−2ax−2py−(b2+q2)=0
x2+y2+2ax+2py+(b2+q2)=0
x2+y2+2ax+2py−(b2+q2)=0

Validate

Go to Question:

Prev Question

Next Question